120p^2-184p+48=0

Solution for 120p^2-184p+48=0 equation:

120p^2-184p+48=0

a = 120; b = -184; c = +48;
Δ = b2-4ac
Δ = -1842-4·120·48
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-184)-104}{2*120}=\frac{80}{240}
=1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-184)+104}{2*120}=\frac{288}{240}
=1+1/5
$